![]() ![]() You’ll need to make that a separate question. Use two trimmers at each end and make sure there’s a support (something that equals 2 trimmers) under each end all the way down to the footing. Fir, then you can reduce it to 5-2x8’s with a grade of No.2 and better. All are pine (per your direction) with a grade of No.1 or better. So, the Total load is 300 plf + 120 plf + 240 plf = 660 plf on beam (assuming the roof joists and ceiling joists span about 12’ each side on the beam). Therefore, 20 psf x 12’ = 240 plf on the beam. The Dead Load of roof framing AND ceiling framing is about 20 psf. You also indicated that the roof structure rests on this wall and it’s not a truss. So, 10psf x 12’ = 120 plf live load on beam. The required Live Load is 10 psf in attic. Then multiply by 25 psf snow load = 300 lbs. So, 6’ on one side + 6’ on other side of beam = 12’. Therefore, if half the span rests on the outside walls, then the remainder rests on the wall. You didn’t give the span of the roof joists that rest on this wall, but I’ll estimate 12’ each side. You have indicated the snow load is about 20-25 lbs. The roof load is comprised of Live Loads (snow load and attic storage load) plus Dead Loads (joists plus ceiling finish, plus insulation plus light fixtures, etc.) This beam is on the second floor and only supports the roof. I’ll assume some dimensions and you tell me if I’m wrong. You’ve given most of the required information in order to size the beam.
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